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Find the Area of a Rhombus Whose Side is 6 Cm and Whose Altitude is 4 Cm. If One of Its Diagonals is 8 Cm Long, Find the Length of the Other Diagonal. - Mathematics

Course
ConceptArea of a Polygon

Question

Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm. If one of its diagonals is 8 cm long, find the length of the other diagonal.

Solution

Given:
Side of the rhombus = 6 cm
Altitude = 4 cm
One of the diagonals = 8 cm
Area of the rhombus = Side x Altitude $= 6 x 4 = 24 {cm}^2 . . . . . . . . (i)$
We know: Area of rhombus $= \frac{1}{2} \times d_1 \times d_2$
Using (i):
$24 = \frac{1}{2} \times d_1 \times d_2$
$24 = \frac{1}{2} \times 8 \times d_2$
$d_2 = 6 cm$

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APPEARS IN

RD Sharma Solution for Mathematics for Class 8 by R D Sharma (2019-2020 Session) (2017 to Current)
Chapter 20: Mensuration - I (Area of a Trapezium and a Polygon)
Ex. 20.1 | Q: 11 | Page no. 14
Solution Find the Area of a Rhombus Whose Side is 6 Cm and Whose Altitude is 4 Cm. If One of Its Diagonals is 8 Cm Long, Find the Length of the Other Diagonal. Concept: Area of a Polygon.
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