#### Question

Find the area of a rhombus if its vertices are (3, 0), (4, 5), (− 1, 4) and (− 2, −1) taken in order. [**Hint:** Area of a rhombus = `1/2` (product of its diagonals)]

#### Solution

Let (3, 0), (4, 5), (−1, 4) and (−2, −1) are the vertices A, B, C, D of a rhombus ABCD.

Length of diagonal AC =`sqrt([3-(-1)]^2 + (0-4)^2)`

Length of diagonal BD =`sqrt([4-(-2)]^2+[5-(-1)]^2)`

`= sqrt(36+36) = 6sqrt2`

Therefore area of rhombus ABCD = `1/2xx4sqrt2xx6sqrt2`

= 24 square units

Is there an error in this question or solution?

Solution Find the area of a rhombus if its vertices are (3, 0), (4, 5), (− 1, 4) and (− 2, −1) taken in order. Concept: Section Formula.