Answer 1

The given figure can be divided into a square, a parallelogram and a trapezium as shown in following figure:

From the above figure:

Area of the figure=(Area of square AGFM with sides 4 cm)+(Area of rectangle MEDN with length 8 cm and width 4 cm)+(Area of trapezium NDCB with parallel sides 8 cm and 3 cm and perpendicular height 4 cm

\[= (4\times4)+(8\times4)+[\frac{1}{2}\times(8+3)\times(4)]\]

\[= 16+32+22\]

\[ {= 70 cm}^2\]