Advertisement Remove all ads

Find the Area Of δAbc Whose Vertices Are: A(-5,7) , B (-4,-5) and C (4,5) - Mathematics

Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads

Find the area of  ΔABC whose vertices are:
A(-5,7) , B (-4,-5) and C (4,5)

 

Advertisement Remove all ads

Solution

A(-5,7) , B (-4,-5) and C (4,5)  are the vertices of .  Δ ABC Then

`(x_1=-5, y_1=7) . (x_2= -4, y_2=-5)  and  (x_3=4,y_3=5)`

Area of triangle ABC

`=1/2 { x_1(y_2-y_3) + x_2 (y_3-y_1) +x_3 (y_1-y_2)}`

`=1/2 {(-5)(-5-5) +(-4)(5-7)+4(7-(5))}`

`=1/2 {(-5) (-10) -4(-2)+4(12)}`

`=1/2 {50+8+48}`

`=1/2 (106)`

= 53 sq . units 

Concept: Area of a Triangle
  Is there an error in this question or solution?

APPEARS IN

RS Aggarwal Secondary School Class 10 Maths
Chapter 16 Coordinate Geomentry
Q 1.2
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×