Advertisement Remove all ads

Find the Area Of δAbc Whose Vertices Are: A( 3,8) , B(-4,2) and C( 5, -1) - Mathematics

Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads

Find the area of  ΔABC whose vertices are:

A( 3,8) , B(-4,2) and C( 5, -1) 

Advertisement Remove all ads

Solution

A( 3,8) , B(-4,2) and C( 5, -1)  are the vertices of ΔABC . Then,

`(x_1 =3, y_1=8),(x_2=-4,y_2=2) and (x_3=5,y_3=-1)`

Area of triangle ABC

`=1/2 {x_1(y_2-y_3) + x_2(y_3-y_1) +x_3(y_1-y_2)}`

`=1/2 {3(2-(-1))+(-4)(-1-8)+5(8-2)}`

`=1/2 {3(2+1)-4(-9)+5(6)}`

`=1/2 {9+36+30}`

`=1/2(75)`

=37.5 sq . units

 

 

Concept: Area of a Triangle
  Is there an error in this question or solution?

APPEARS IN

RS Aggarwal Secondary School Class 10 Maths
Chapter 16 Coordinate Geomentry
Q 1.3
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×