Advertisement Remove all ads

Find the Angle Subtended at the Origin by the Line Segment Whose End Points Are (0, 100) and (10, 0) - Mathematics

Find the angle subtended at the origin by the line segment whose end points are (0, 100) and (10, 0).

Advertisement Remove all ads

Solution

Let the given points be A(0,100), B(10,0) and the origin be denoted by o(0,0)

We know that

In a right angled triangle the angle oppposite the hypotenuse subtend an angle of 90°

Let us find distance AB, AO, BO

`AB = sqrt((10 - 0)^2 + (0 - 100)^2)`

`= sqrt(100 + 10000)`

`= sqrt(10100)` units

`AO = sqrt((0 - 0)^2 + (0 - 100)^2)`

= `sqrt(100)` untis

Her we can see that, `AO^2 + BO^2 = AB^2`

Therefore, ΔAOB is a right angled triangle with AB being the hypotenuse.

So the angle subtended at the origin by the giving line segment is 90°

  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

RD Sharma Class 10 Maths
Chapter 6 Co-Ordinate Geometry
Exercise 6.2 | Q 53 | Page 17
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×