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Find the Angle Subtended at the Centre of Circle of Radius 5cm by an Arc of Length `((5pi)/3)` Cm - Mathematics

Find the angle subtended at the centre of circle of radius 5cm by an arc of length `((5pi)/3)` cm

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Solution

Radius (r) = 5 cm

𝜃 = angle subtended at centre (degrees)

Length of Arc =`theta/360^@`× 2𝜋r cm

But arc length =`5pi/3`𝑐𝑚

`theta/360^@× 2pi × 5 =(5pi)/3`

`theta=(360^@×pi)/(3×2pi)= 60^@`

∴ Angle subtended at centre = 60°

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APPEARS IN

RD Sharma Class 10 Maths
Chapter 13 Areas Related to Circles
Exercise 13.2 | Q 2 | Page 24
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