#### Question

The electric field inside a parallel plate capacitor is E. Find the amount of work done in moving a charge q over a closed loop a b c d a.

#### Solution

Work done, W= F.d

Here, *F *is the force exerted on the charge (q) due to electric field *(E*) and is given by:

F=qE

Net displacement, *d* = 0

∴ W=0

Is there an error in this question or solution?

Solution Find the Amount of Work Done in Moving a Charge Q Over a Closed Loop a B C D A. Concept: Combination of Capacitors.