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Find the Amount of Work Done in Moving a Charge Q Over a Closed Loop a B C D A. - Physics

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The electric field inside a parallel plate capacitor is E. Find the amount of work done in moving a charge q over a closed loop a b c d a.

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Solution

Work done, W= F.d

Here, F is the force exerted on the charge (q) due to electric field (E) and is given by:

F=qE

Net displacement, d = 0

 W=0

Concept: Combination of Capacitors
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