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# Find the altitude of a trapezium whose area is 65 cm2 and whose bases are 13 cm and 26 cm. - Mathematics

Sum

Find the altitude of a trapezium whose area is 65 cm2 and whose bases are 13 cm and 26 cm.

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#### Solution

Given:
Area of the trapezium=65 cm2
The lengths of the opposite parallel sides are 13 cm and 26 cm.
Area of trapezium$=\frac{1}{2}\times(\text{ Sum of parallel bases })\times(\text{ Altitude })$
On putting the values:
$65 = \frac{1}{2} \times (13 + 26) \times (\text{ Altitude })$
$65 \times 2 = 39 \times\text{ Altitude }$
$\text{ Altitude }=\frac{130}{39}=\frac{10}{3}cm$

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#### APPEARS IN

RD Sharma Class 8 Maths
Chapter 20 Mensuration - I (Area of a Trapezium and a Polygon)
Exercise 20.2 | Q 5 | Page 22
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