# Find All Possible Values of X for Which the Distance Between the Points A(X,-1) and B(5,3) is 5 Units. - Mathematics

Find all possible values of x for which the distance between the points

A(x,-1) and B(5,3) is 5 units.

#### Solution

Given AB = 5 units

Therefore, (AB)2 = 25 units

⇒(5-a)^2 +{3-(-1)}^2 = 25

⇒(5-a)^2+(3+1)^2 = 25

⇒(5-a)^2 + (4)^2 =25

⇒(5-a)^2 +16 =25

⇒(5-a)^2 =25-16

⇒(5-a)^2 = 9

⇒(5-a)=+-sqrt(9)

⇒ 5-a=+-3

⇒5-a =3 or 5-a=-3

⇒ a=2 or 8

Therefore, a = 2 or 8.

Concept: Distance Formula
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#### APPEARS IN

RS Aggarwal Secondary School Class 10 Maths
Chapter 16 Coordinate Geomentry
Q 3