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Sum
Find :-
`32^(2/5)`
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Solution
`32^(2/5) = (2^5)^(2/5) = 2^(5xx2/5) = 2^2 = 4`
Concept: Introduction of Real Number
Is there an error in this question or solution?
Find :-
`32^(2/5)`
`32^(2/5) = (2^5)^(2/5) = 2^(5xx2/5) = 2^2 = 4`