Fill in the blanks in following table:
|
P(A) |
P(B) |
P(A ∩ B) |
P(A ∪ B) |
|
|
|
0.35 |
… |
0.25 |
0.6 |
Advertisement Remove all ads
Solution
Here, P(A) = 0.35, P(A ∩ B) = 0.25, P(A ∪ B) = 0.6
We know that P(A ∪ B) = P(A) + P(B) – P(A ∩ B)
∴0.6 = 0.35 + P(B) – 0.25
⇒ P(B) = 0.6 – 0.35 + 0.25
⇒ P(B) = 0.5
Concept: Axiomatic Approach to Probability
Is there an error in this question or solution?
Advertisement Remove all ads
APPEARS IN
Advertisement Remove all ads
Advertisement Remove all ads
