Factorize the Following Expressions: 8a3 - B3 - 4ax + 2bx - Mathematics

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Factorize the following expressions:

8a3 - b3 - 4ax + 2bx

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Solution

= 8a3  - b3  - 2x (2a - b)

= (2a )3 - b3 - 2x (2a - b)

= (2a - b)((2a)2 + 2a ´ b + b2 )- 2x (2a - b)                    [∵ a3 - b3  = (a - b)(a2 + ab + b2 )]

= (2a - b)(4a2  + 2ab + b2 ) - 2x (2a - b)

= (2a - b)(4a2 + 2ab + b2 - 2x)

∴ 8a3 - b3 - 4ax + 2bx = (2a - b)(4a2 + 2ab + b2 - 2x)

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Chapter 5: Factorisation of Algebraic Expressions - Exercise 5.2 [Page 14]

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RD Sharma Mathematics for Class 9
Chapter 5 Factorisation of Algebraic Expressions
Exercise 5.2 | Q 24 | Page 14

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