Factorize the Following Expressions 64a3 – B3 - Mathematics

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Factorize the following expressions

64a3 – b3

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Solution

= (4a)3 - b3

= (4a - b)((4a)2 + 4a b + b2)          [∵ a3 - b3  = (a - b)(a2 + ab + b2)]

= (4a - b)(16a2  + 4ab + b2)

∴ 64a3  - b3   = (4a - b)(16a2 + 4ab + b2)

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Chapter 5: Factorisation of Algebraic Expressions - Exercise 5.2 [Page 14]

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RD Sharma Mathematics for Class 9
Chapter 5 Factorisation of Algebraic Expressions
Exercise 5.2 | Q 5 | Page 14

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