Factorize A2 + 4b2 - 4ab - 4c2 - Mathematics

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Factorize  a2 + 4b2 - 4ab - 4c2

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Solution

On rearranging

= a2 - 4ab + 4b2 - 4c2

= (a)2 - 2 x a x 2b + (2b)2 - 4c2

Using identity a2 - 2ab + b2  = (a - b)2

= (a - 2b)2 - 4c2

= (a - 2b)2 - (2c)2

Using identity a2 - b2 = (a + b)(a - b)

= (a - 2b + 2c)(a - 2b - 2c)

∴ a2  + 4b2  - 4ab - 4c2  = (a - 2b + 2c)(a - 2b - 2c)

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Chapter 5: Factorisation of Algebraic Expressions - Exercise 5.1 [Page 9]

APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 5 Factorisation of Algebraic Expressions
Exercise 5.1 | Q 11 | Page 9

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