Factorize 64a3 +125b3 + 240a2b + 300ab2 - Mathematics

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Factorize 64a3 +125b3 + 240a2b + 300ab2

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Solution

64a3 +125b3 + 240a2b + 300ab2

= (4a)3 + (5b)3 + 3 x (4a)2 x 5b + 3(4a)(5b)2

= (4a + 5b)3           [∵ a3 + b3 + 3a2b + 3ab2  = (a + b)3]

= (4a + 5b)(4a + 5b)(4a + 5b)

∴ 64a3 +125b3 + 240a2b + 300ab2 = (4a + 5b)(4a + 5b)(4a + 5b)

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Chapter 5: Factorisation of Algebraic Expressions - Exercise 5.3 [Page 17]

APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 5 Factorisation of Algebraic Expressions
Exercise 5.3 | Q 1 | Page 17

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