Factorize 2a^2 + 2 Sqrt6ab + 3b^2 - Mathematics

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Factorize `2a^2 + 2  sqrt6ab + 3b^2`

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Solution

`= (2sqrta)^2 + 2 xx sqrt2a xx sqrt3b + (sqrt3b)^2`

Using identity a2  + 2ab + b2  = (a + b)2

`= (sqrt2a + sqrt3b)^2`

`= (sqrt2a + sqrt3b)(sqrt2a + sqrt3b)`

`∴ 2a^2 + 2sqrt6ab + 3b^2 = (sqrt2a + sqrt3b)(sqrt2a + sqrt3b)`

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Chapter 5: Factorisation of Algebraic Expressions - Exercise 5.1 [Page 9]

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RD Sharma Mathematics for Class 9
Chapter 5 Factorisation of Algebraic Expressions
Exercise 5.1 | Q 20 | Page 9

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