Maharashtra State BoardSSC (English Medium) 8th Standard
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Factorise : Y3 − 27 - Mathematics

Sum

Factorise :

y− 27

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Solution

It is known that,

\[a^3  -  b^3    =   \left( a - b \right)\left( a^2 + b^2 + ab \right)\]

\[\   y^3  - 27\] 

\[ =    \left( y \right)^3  -  \left( 3 \right)^3 \] 

\[ = \left( y - 3 \right)\left\{ \left( y \right)^2 + \left( 3 \right)^2 + \left( y \right) \times \left( 3 \right) \right\}\] 

\[ = \left( y - 3 \right)  \left( y^2 + 9 + 3y \right)\]

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APPEARS IN

Balbharati Mathematics 8th Standard Maharashtra State Board
Chapter 6 Factorisation of Algebraic expressions
Practice Set 6.3 | Q 1.1 | Page 32
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