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Factorise. Y 3 + 1 8 Y 3 - SSC (English Medium) Class 8 - Mathematics

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Question

Factorise.

`y^3 + 1/(8y^3)`

Solution

It is known that,

\[a^3  +  b^3  = \left( a + b \right)\left( a^2 + b^2 - ab \right)\]

\[\   y^3  + \frac{1}{8 y^3}\] 

\[ =  \left( y \right)^3  +  \left( \frac{1}{2y} \right)^3 \] 

\[ = \left( y + \frac{1}{2y} \right)\left\{ \left( y \right)^2 + \left( \frac{1}{2y} \right)^2 - \left( y \right) \times \left( \frac{1}{2y} \right) \right\}\] 

\[ = \left( y + \frac{1}{2y} \right)\left( y^2 + \frac{1}{4 y^2} - \frac{1}{2} \right)\]

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APPEARS IN

 Balbharati Solution for Balbharati Class 8 Mathematics (2019 to Current)
Chapter 6: Factorisation of Algebraic expressions
Practice Set 6.2 | Q: 6 | Page no. 31
Solution Factorise. Y 3 + 1 8 Y 3 Concept: Factors of A3 + B3.
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