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Factorise: X3 − 64y3 - SSC (English Medium) Class 8 - Mathematics

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Question

Factorise:

x− 64y3

Solution

It is known that,

\[a^3  -  b^3    =   \left( a - b \right)\left( a^2 + b^2 + ab \right)\]

\[\  x^3  - 64 y^3 \] 

\[ =  \left( x \right)^3  -  \left( 4y \right)^3 \] 

\[ = \left( x - 4y \right)\left\{ \left( x \right)^2 + \left( 4y \right)^2 + \left( x \right) \times \left( 4y \right) \right\}\] 

\[ = \left( x - 4y \right)\left( x^2 + 16 y^2 + 4xy \right)\]

  Is there an error in this question or solution?

APPEARS IN

 Balbharati Solution for Balbharati Class 8 Mathematics (2019 to Current)
Chapter 6: Factorisation of Algebraic expressions
Practice Set 6.3 | Q: 1.2 | Page no. 32
Solution Factorise: X3 − 64y3 Concept: Factors of A3 - B3.
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