Maharashtra State BoardSSC (English Medium) 8th Standard
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Factorise: X3 − 64y3 - Mathematics

Sum

Factorise:

x− 64y3

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Solution

It is known that,

\[a^3  -  b^3    =   \left( a - b \right)\left( a^2 + b^2 + ab \right)\]

\[\  x^3  - 64 y^3 \] 

\[ =  \left( x \right)^3  -  \left( 4y \right)^3 \] 

\[ = \left( x - 4y \right)\left\{ \left( x \right)^2 + \left( 4y \right)^2 + \left( x \right) \times \left( 4y \right) \right\}\] 

\[ = \left( x - 4y \right)\left( x^2 + 16 y^2 + 4xy \right)\]

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APPEARS IN

Balbharati Mathematics 8th Standard Maharashtra State Board
Chapter 6 Factorisation of Algebraic expressions
Practice Set 6.3 | Q 1.2 | Page 32
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