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Sum
Factorise the following:
3a² – 24ab + 48b²
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Solution
3a2 – 24ab + 48b2 = 3[a2 – 8ab + 16b2]
= 3[a2 – 2 × a × 4b + (4b)2]
= 3(a – 4b)2 ...[a2 – 2ab + b2 = (a – b)2]
Concept: Factorisation Using Identity a2 - 2ab + b2 = (a - b)2
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