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Sum

Factorise the following:

3a² – 24ab + 48b²

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#### Solution

3a^{2} – 24ab + 48b^{2} = 3[a^{2} – 8ab + 16b^{2}]

= 3[a^{2} – 2 × a × 4b + (4b)^{2}]

= 3(a – 4b)^{2} ...[a^{2} – 2ab + b^{2} = (a – b)^{2}]

Concept: Factorisation Using Identity a2 - 2ab + b2 = (a - b)2

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