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Sum
Factorise completely: 5ap2 + 11ap + 2a
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Solution
5ap2 + 11ap + 2a = a[5p2 + 11p + 2]
= a[5p2 + 10p + p +2]
= a[5p(p+2) + 1(p + 2)]
= a[(p + 2)(5p + 1)]
= a (p + 2) (5p + 1)
Concept: Factorising Completely
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