Factorise Completely: 2a2 - 8a - 64 - Mathematics

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Sum

Factorise completely: 2a2 - 8a - 64 

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Solution

2a2 - 8a - 64 = 2[a2 - 4a - 32]

= 2[a2 - 8a + 4a - 32]

= 2[a(a - 8) + 4(a - 8)]

= 2[(a - 8) (a + 4)]

= 2(a - 8)(a + 4)

Concept: Factorising Completely
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Chapter 13: Factorisation - Exercise 13 (E) [Page 162]

APPEARS IN

Selina Concise Mathematics Class 8 ICSE
Chapter 13 Factorisation
Exercise 13 (E) | Q 12 | Page 162
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