Factorise :- 8a^3 + b^3 + 12a^2b + 6ab^2 - Mathematics

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Factorise :- 8a3 + b3 + 12a2b + 6ab2 

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Solution

8ab12a26ab2 (2a)3 b3 3(2a)23(2a)(b)2

                                      = (2b)3

                                      = (2b)(2b)(2b)

Concept: Algebraic Identities
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Chapter 2: Polynomials - Exercise 2.5 [Page 49]

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NCERT Class 9 Maths
Chapter 2 Polynomials
Exercise 2.5 | Q 8.1 | Page 49

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