Factorise : 6xy(A2 + B2) + 8yz(A2 + B2) -10xz(A2 + B2) - Mathematics

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Sum

Factorise : 6xy(a2 + b2) + 8yz(a2 + b2) -10xz(a2 + b2

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Solution

6xy(a2 + b2) + 8yz(a2 + b2) -10xz(a2 + b2)

= H.C.F. of 6, 8, 10 = 2 , then

2(a2 + b2) (3xy + 4yz - 5xz)

  Is there an error in this question or solution?
Chapter 13: Factorisation - Exercise 13 (A) [Page 157]

APPEARS IN

Selina Concise Mathematics Class 8 ICSE
Chapter 13 Factorisation
Exercise 13 (A) | Q 17 | Page 157
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