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Factorise :- 64a^3 – 27b^3 – 144a^2 b + 108ab^2 - Mathematics

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Factorise :- 64a3 – 27b3 – 144a2b + 108ab2 

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Solution

64a3 – 27b3 – 144a2108ab2 (4a)3 – (3b)3 – 3(4a)2(3b3(4a)(3b)2

(4– 3b)3

(4– 3b)(4– 3b)(4– 3b)

Concept: Algebraic Identities
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APPEARS IN

NCERT Class 9 Maths
Chapter 2 Polynomials
Exercise 2.5 | Q 8.4 | Page 49

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