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Factorise :- 27y^3 + 125z^3 - Mathematics

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Factorise :- 27y3 + 125z3

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Solution

27y3 125z3 (3y)3 (5z)3

                     = (35z)[(3y)2 – (3y)(5z(5z)2]                   [∵ a3 + b3 = (a + b)(a2 + b2 - ab)]

                     = (35z)(9y2 – 15y25z)2 

Concept: Algebraic Identities
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APPEARS IN

NCERT Class 9 Maths
Chapter 2 Polynomials
Exercise 2.5 | Q 10.1 | Page 49

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