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Factorise :- 27x^3 + y^3 + z^3 – 9xyz - Mathematics

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Factorise :- 27x3 + y3 + z3 – 9xyz

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Solution

It is known that,

x3 + y3 + z3 - 3xyz = (x + y + z)(x2 + y2 + z2 - xy - yz - zx)

∴ 27x3 y3 z3 – 9xy(3x)3 y3 z3 – 3(3x)(y)(z)

                                    = (3z)(3x)2 y2 z2 – 3x– y– 3xz

                                    = (3z)(9x2 y2 z2 – 3x– y– 3xz)

Concept: Algebraic Identities
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APPEARS IN

NCERT Class 9 Maths
Chapter 2 Polynomials
Exercise 2.5 | Q 11 | Page 49

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