Factorise :- 27p^3-1/216-(9/2)p^2+(1/4)p - Mathematics

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Factorise :-

`27p^3-1/216-9/2p^2+1/4p`

 

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Solution

`27p^3-1/216-9/2p^2+1/4p = (3p)^3-(1/6)^3-3(3p)^2(1/6)+3(3p)(1/6)^2`

`= (3p-1/6)^3`

`= (3p-1/6)(3p-1/6)(3p-1/6)`

 

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Chapter 2: Polynomials - Exercise 2.5 [Page 49]

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NCERT Mathematics Class 9
Chapter 2 Polynomials
Exercise 2.5 | Q 8.5 | Page 49

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