Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads
Factorise :-
`27p^3-1/216-9/2p^2+1/4p`
Advertisement Remove all ads
Solution
`27p^3-1/216-9/2p^2+1/4p = (3p)^3-(1/6)^3-3(3p)^2(1/6)+3(3p)(1/6)^2`
`= (3p-1/6)^3`
`= (3p-1/6)(3p-1/6)(3p-1/6)`
Concept: Algebraic Identities
Is there an error in this question or solution?
