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Factorise :- 27 – 125a3 – 135a + 225a2
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Solution
27 – 125a3 – 135a + 225a2 = 33 – (5a)3 – 3(3)2(5a) + 3(3)(5a)2
= (3 – 5a)3
= (3 – 5a)(3 – 5a)(3 – 5a)
Concept: Algebraic Identities
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