#### Question

Find the value of k, if x – 1 is a factor of p(x) in the following case:- p(x) = x^{2} + x + k

#### Solution

If *x* − 1 is a factor of polynomial *p*(*x*), then *p*(1) must be 0.

*p*(*x*) = *x*^{2} + *x* + *k*

*p*(1) = 0

⇒ (1)^{2} + 1 + *k* = 0

⇒ 2 + *k* = 0

⇒ *k* = −2

Therefore, the value of* k *is −2*.*

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#### APPEARS IN

Solution Find the value of k, if x – 1 is a factor of p(x) in the following case:- p(x) = x^2 + x + k Concept: Factorisation of Polynomials.