If the solubility product of CuS is 6 × 10−16, calculate the maximum molarity of CuS in aqueous solution.
Solubility product of CuS, Ksp = 6 × 10−16
Let s be the solubility of CuS in mol L−1.
CuS ↔ Cu2+ + S2-
Now K_(sp) = [Cu2+][S2-]
Then, we have, Ksp = s2 = 6 x10-16
`=> s = sqrt(6xx10^(-16)) `
= 2.45 × 10−8 mol L−1
Hence, the maximum molarity of CuS in an aqueous solution is 2.45 × 10−8 mol L−1