Express each one of the following in terms of trigonometric ratios of angles lying between
0° and 45°
Sin 59° + cos 56°
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Solution
We have `sin (90^@ - theta) = cos theta` and `cos(90^@ - theta) = sin theta` so
`sin 596@ + cos 56^@ = sin(90^@ - 31^@) + cos 90^@ (90^@ - 34^@)`
`= cos 31^@ + sin 34^@`
Thus the desired expression is `cos 31^@ + sin 34^@`
Is there an error in this question or solution?
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