Express each one of the following in terms of trigonometric ratios of angles lying between 0° and 45°
cot 85° + cos 75°
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Solution
We know that `cot (90^@ - theta) = tan theta` and `cos (90^@ - theta) = sin theta` so
`cot 85° + cos 75° = cot(90^@ - 5^@) + cos(90^@ - 15^@)`
`= tan 5^@ +sin 15^@`
Thus the desired expression is `tan 56^@ + sin 15^@`
Is there an error in this question or solution?
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