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Explain What Would Happen If in the Capacitor Given in Exercise 2.8, a 3 Mm Thick Mica Sheet Were Inserted Between the Plates - Physics

Explain what would happen if in the capacitor given in Exercise 2.8, a 3 mm thick mica sheet (of dielectric constant = 6) were inserted between the plates,

(a) While the voltage supply remained connected.

(b) After the supply was disconnected.

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Solution

(a) Dielectric constant of the mica sheet, k = 6

Initial capacitance, C = 1.771 × 10−11 F

New Capacitance, C''=kC=`6xx1.771xx10^-11=106 pF`

Supply voltage, = 100 V

New Capacitance, q'=C'V=`6xx1.771xx10^-9=1.06 xx 10^-8pF`

Potential across the plates remains 100 V.

(b) Dielectric constant, k = 6

Initial capacitance, C = 1.771 × 10−11 F

New Capacitance, C''=kC=`6xx1.771xx10^-11=106 pF`

If supply voltage is removed, then there will be no effect on the amount of charge in the plates.

Charge = 1.771 × 10−9 C

Potential across the plates is given by,

`therefore V'=q/C'`

`=(1.771xx10^-9)/(106xx10^-12)`

=16.7 V

Concept: Energy Stored in a Capacitor
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