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Solution - Estimate the Speed with Which Electrons Emitted from a Heated Emitter of an Evacuated Tube Impinge on the Collector Maintained at a Potential Difference of 500 V with Respect to the Emitter. - Experimental Study of Photoelectric Effect

ConceptExperimental Study of Photoelectric Effect

Question

Estimate the speed with which electrons emitted from a heated emitter of an evacuated tube impinge on the collector maintained at a potential difference of 500 V with respect to the emitter. Ignore the small initial speeds of the electrons. The specific charge of the electron, i.e., its e/m is given to be 1.76 × 1011 C kg−1.

Solution

Potential difference across the evacuated tube, V = 500 V

Specific charge of an electron, e/m = 1.76 × 1011 C kg−1

The speed of each emitted electron is given by the relation for kinetic energy as:

KE = 1/2 mv^2 = eV

:. v = ((2eV)/m)^(1/2)  = (2V xx e/m)^(1/2)

= (2 xx 500 xx 1.76 xx 10^11)^(1/2) = 1.327 xx 10^ "m/s"

Therefore, the speed of each emitted electron is 1.327 xx 10^7 "m/s"

Is there an error in this question or solution?

APPEARS IN

NCERT Physics Textbook for Class 12 Part 2
Chapter 11: Dual Nature of Radiation and Matter
Q: 20.1 | Page no. 409

Reference Material

Solution for question: Estimate the Speed with Which Electrons Emitted from a Heated Emitter of an Evacuated Tube Impinge on the Collector Maintained at a Potential Difference of 500 V with Respect to the Emitter. concept: Experimental Study of Photoelectric Effect. For the courses CBSE (Arts), CBSE (Commerce), CBSE (Science)
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