Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 9th
Advertisement Remove all ads

Expand the following: (3a + 1)(3a – 2)(3a + 4) - Mathematics

Sum

Expand the following:

 (3a + 1)(3a – 2)(3a + 4)

Advertisement Remove all ads

Solution

(3a + 1)(3a – 2)(3a + 4)

(x + a)(x + b)(x + c) ≡ x3 + (a + b + c) x2 + (ab + bc + ca) x + abc

(3a + 1)(3a – 2)(3a + 4) = (3a)3 + (1 – 2 + 4)(3a)2 + [1 × (– 2) + (– 2 × 4) + 4 × 1] (3a) + 1 × – 2 × 4

= 27a3 + 3(9a2) + (– 2 – 8 + 4) 3a – 8

= 27a3 + 27a2 – 8a – 8

  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

Samacheer Kalvi Mathematics Class 9th Tamil Nadu State Board
Chapter 3 Algebra
Exercise 3.4 | Q 1. (iv) | Page 101
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×