Maharashtra State BoardSSC (English Medium) 8th Standard
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Expand. (9x−5t)(9x+3t) - Mathematics

Sum

Expand.

(9x−5t) (9x+3t)

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Solution

(9x−5t) (9x+3t)

= (9x)2 + {(-5t) + (3t)} (9x) + (-5t)×(3t)

= 81x2 + (-2t)(9x) - 15t2

= 81x2 - 18xt - 15t2

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APPEARS IN

Balbharati Mathematics 8th Standard Maharashtra State Board
Chapter 5 Expansion formulae
Practice Set 5.1 | Q 6 | Page 24
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