Maharashtra State BoardSSC (English Medium) 8th Standard
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Expand. ( 1 Y + 4 ) ( 1 Y − 9 ) - Mathematics

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Sum

Expand.

`(1/y+4)(1/y-9)`

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Solution

`(1/y+4)(1/y-9)`

= `(1/y)^2 + {4 + (-9)}1/y + (4) xx (-9)`

= `1/y^2 + (-5) xx 1/y -36`

= `1/y^2 -5/y - 36`

Concept: Expansion of (x + a)(x + b)
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APPEARS IN

Balbharati Mathematics 8th Standard Maharashtra State Board
Chapter 5 Expansion formulae
Practice Set 5.1 | Q 9 | Page 24
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