HSC Arts 12th Board ExamMaharashtra State Board
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Solution for Prove that : ∫√(a2−x2)dx=x/2 √(a^2−x^2)=a^2/2 sin^−1(x/a)+c - HSC Arts 12th Board Exam - Mathematics and Statistics

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Question

Prove that : `int sqrt(a^2-x^2)dx=x/2sqrt(a^2-x^2)=a^2/2sin^-1(x/a)+c`

 

 

Solution

`intsqrt(a^2-x^2)dx`

Substitute x = asinθ ...(i)

dx = acosθ dθ
The integral becomes

`intsqrt(a^2-a^2sin^2theta)acostheta d theta`

`=intasqrt(1-sin^2theta)acostheta d theta`

`=a^2intcos^2theta d theta`

`=a^2int(1+cos2theta)/2 d theta`

`=a^2[int1/2d theta+int(cos2theta)/2d theta]`

`=(a^2theta)/2+a^2/4sin2theta+C`

`"From "(i) ,theta=sin^-1(x/a),sin2theta=2sinthetacostheta=2(x/a)sqrt(1-(x^2/a^2))=(2x)/a^2sqrt(a^2-x^2)`

Substituting these values, we get

 

`intsqrt(a^2-x^2)dx=a^2/2sin^-1(x/a)+a^2/4xx(2x)/a^2sqrt(a^2-x^2)+C`

`=a^2/2sin^-1(x/a)+x/2sqrt(a^2-x^2)+C " (Proved)"`

 

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APPEARS IN

 2015-2016 (March) (with solutions)
Question 5.2.2 | 4.00 marks

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Solution Prove that : ∫√(a2−x2)dx=x/2 √(a^2−x^2)=a^2/2 sin^−1(x/a)+c Concept: Evaluation of Definite Integrals by Substitution.
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