Question
Evaluate :`int_0^(pi/2)1/(1+cosx)dx`
clickto share
Solution
`int_0^(pi/2)1/(1+cosx)dx`
Solving the integral without limits,
`int1/(1+cosx)dx`
`=int1/(2cos^2 (x/2))dx`
`=1/2intsec^2 (x/2)dx`
`=1/2[tan(x/2)/(1/2)]+C`
`=tan(x/2)+C`
Substituting the limits,we get
`=[tan(x/2)]_0^(pi/2)`
`=[tan (pi/4)-tan0]`
= 1
Is there an error in this question or solution?
Solution for question: Evaluate :∫π/2 0 1/(1+cosx)dx concept: Evaluation of Definite Integrals by Substitution. For the courses HSC Arts, HSC Science (Computer Science), HSC Science (Electronics), HSC Science (General)