#### Question

Evaluate: `int1/(xlogxlog(logx))dx`

#### Solution

`Let I= int1/(x.logxlog(logx))dx`

*Put log (lo*g x) = t

Differentiating w.r.t. x, we get

`1/logx.1/xdx=dt`

`I=int1/tdt=log|t|+c`

`I=log|log(logx)|+c`

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#### APPEARS IN

Solution Evaluate: ∫1/(x logx log(logx))dx Concept: Evaluation of Definite Integrals by Substitution.