#### Question

Evaluate :

`∫_(-pi)^pi (cos ax−sin bx)^2 dx`

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#### Solution

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#### Reference Material

Solution for question: ∫π−π (cos ax−sin bx)2 dx concept: Evaluation of Definite Integrals by Substitution. For the courses CBSE (Arts), CBSE (Commerce), CBSE (Science), HSC Arts, HSC Science (Computer Science), HSC Science (Electronics), HSC Science (General) , ISC (Arts), ISC (Commerce), ISC (Science), PUC Karnataka Science