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Evaluate sin18°/cos72° - CBSE Class 10 - Mathematics

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Question

Evaluate `(sin 18^@)/(cos 72^@)`

Solution

`(sin 18^@)/(cos72^@) = (sin(90^@ - 72^@))/cos 72^@`

`= (cos 72^@)/(cos 72^@) = 1`

 

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APPEARS IN

 NCERT Solution for Mathematics Textbook for Class 10 (2019 to Current)
Chapter 8: Introduction to Trigonometry
Ex. 8.30 | Q: 1.1 | Page no. 189
Solution Evaluate sin18°/cos72° Concept: Trigonometric Ratios of Complementary Angles.
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