CBSE Class 10CBSE
Share
Notifications

View all notifications

Evaluate: `Sin 18^@/Cos 72^@ + Sqrt3 [Tan 10° Tan 30° Tan 40° Tan 50° Tan 80°]` - CBSE Class 10 - Mathematics

Login
Create free account


      Forgot password?

Question

Evaluate: `sin 18^@/cos 72^@  + sqrt3 [tan 10° tan 30° tan 40° tan 50° tan 80°]`

Solution

sin 18° = sin (90° - 72) = cos 72°

tan 10° = cot 80° tan 50° = cot 40°

`=> sin 18^@/sin 18^@ + sqrt3 [tan 80 cos 30 . tan 40 cot 40 . 1/sqrt3]`

`= 1 + sqrt3 . 1/sqrt3 = 2`

  Is there an error in this question or solution?

APPEARS IN

Solution Evaluate: `Sin 18^@/Cos 72^@ + Sqrt3 [Tan 10° Tan 30° Tan 40° Tan 50° Tan 80°]` Concept: Trigonometric Ratios of Some Specific Angles.
S
View in app×