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Evaluate : `intsec^nxtanxdx`
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Solution
`I=intsec^(n-1)xsecxtanx dx`
Let secx=t
`therefore secxtanx dx=dt`
`I=intt^(n-1)dt`
`=t^n/n+c`
`=sec^nx/n+C`
Concept: Properties of Definite Integrals
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