Answer 1

We have to find:

`tan 35^@/cot 55^@  + cot 78^@/tan 12^@  -1`

since `tan (90^@ - theta) = cot theta` and `cot (90^@ - theta) = tan theta`

 = 1

So value of `(tan 35^@)/(cot 55^@) + (cot 78^@)/(tan 12^@)` is 1