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Evaluate cos 48° − sin 42° - Mathematics

Evaluate cos 48° − sin 42°

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Solution

We have to find cos 48° − sin 42°

Since `cos (90^@ - theta) = sin theta` So

`cos 48^@ - sin 42^@  = cos (90^@ - 42^@) - sin 42^@`

`= sin 42^@ - sin 42^@`

= 0

So value of `cos 48^@ - sin 42^@` is 0

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APPEARS IN

NCERT Class 10 Maths
Chapter 8 Introduction to Trigonometry
Exercise 8.3 | Q 1.3 | Page 189
RD Sharma Class 10 Maths
Chapter 10 Trigonometric Ratios
Exercise 10.3 | Q 2.02 | Page 53
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