Answer 1

We have to find cos 48° − sin 42°

Since `cos (90^@ - theta) = sin theta` So

`cos 48^@ - sin 42^@  = cos (90^@ - 42^@) - sin 42^@`

`= sin 42^@ - sin 42^@`

= 0

So value of `cos 48^@ - sin 42^@` is 0