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Evaluate : 7^0 X (25)^(-3/2) - 5^(-3) - Mathematics

Sum

Evaluate :
`7^0 xx (25)^(-3/2) - 5^(-3)`

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Solution

`7^0 xx (25)^(-3/2) - 5^(-3)`
= `7^0 xx ( 5 xx 5 )^( -3/2 ) - 5^( -3 )`

= `7^0 xx (5^2)^(-3/2) - 1/5^3`

= `7^0 xx [(5)^[2 xx (-3/2)]] - 1/5^3`

= `7^0 xx 5^(-3) - 1/5^3`

= `1 xx 5^(-3)- 1/5^3`

= `1/5^3 - 1/5^3`

= `[ 1 - 1 ]/[ 5 xx 5 xx 5 ]`

= `0/125`

= 0

Concept: Laws of Exponents
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APPEARS IN

Selina Concise Mathematics Class 9 ICSE
Chapter 7 Indices (Exponents)
Exercise 7 (A) | Q 1.4 | Page 98
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